Purpose
Find items that contain specified minimum or maximum criteria
Display attribute values for items that contain specified minimum or maximum criteria.
Assumptions
A Parts table has the following values for Order items.
id |
partno |
rev |
i1 |
1 |
5 |
i1 |
1 |
2 |
i1 |
2 |
3 |
i1 |
3 |
1 |
i2 |
1 |
'1 |
i2 |
2 |
2 |
i2 |
5 |
1 |
Query Expressions
Several types of query expressions can be created using the min/max functionality.
listitems expression for normal TADB groups. |
|
listitems expression for list TADB groups. |
|
getvalues expression for normal TADB groups |
|
getvalues expression for list TADB groups |
listitems expression for normal TADB Groups
listitems "orders","parts.rev=max()"
Where
Criteria |
Is/are the: |
orders |
item type |
Parts |
Table name |
rev |
Revision number |
max() |
Maximum value |
The Query expression asks:
Which Order type item or items has/have the maximum revision number in the Parts table.
The answer is:
The maximum rev in the table is 5. The Order item returned is i1.
id |
partno |
rev |
i1 |
1 |
5 |
i1 |
1 |
2 |
i1 |
2 |
3 |
i1 |
3 |
1 |
i2 |
1 |
1 |
i2 |
2 |
2 |
i2 |
5 |
1 |
listitems expression for list TADB groups
listitems "orders","parts(partno='2').min(rev)"
Where
Criteria |
Is/are the: |
orders |
item type |
Parts |
Table name |
partno |
Part number |
2 |
Part number value to be included in the query. |
min() |
Minimum value |
rev |
Revision number |
The Query expression asks:
Which Order items that have a part number of 2 have the minimum revision number?
The answer is:
i2, part number 2
Two items have a part number of 2; the i2 item has the minimum revision number of those part numbers, which is 2.
id |
partno |
rev |
i1 |
1 |
5 |
i1 |
1 |
2 |
i1 |
2 |
3 |
i1 |
3 |
1 |
i2 |
1 |
1 |
i2 |
2 |
2 |
i2 |
5 |
1 |
getvalues expression for normal TADB groups
getvalues "i1","parts(rev=max()).partno"
Where
Criteria |
Is/are the: |
i1 |
Part id attribute value |
Parts |
Table name |
rev |
Revision number |
max() |
Maximum value |
partno |
Part number |
The Query expression asks:
Get the part number of the i1 item that has the maximum rev number.
The answer is:
1
partno 1 has the greatest rev for item i1, which is 5.
id |
partno |
rev |
i1 |
1 |
5 |
i1 |
1 |
2 |
i1 |
2 |
3 |
i1 |
3 |
1 |
i2 |
1 |
1 |
i2 |
2 |
2 |
i2 |
5 |
1 |
getvalues expression for list TADB groups
getvalues "i1","parts(partno='1').min(rev).rev"
Where
Criteria |
Is/are the: |
i1 |
Part id attribute value |
Parts |
Table name |
partno |
Part number |
1 |
Part number to be queried |
min() |
Minimum value |
rev |
Revision number attribute to return |
The Query expression asks:
What is the minimum revision number for i1 items that have a 1 part number.
The answer is:
2
Records for item i1 with partno 1 have 2 rev values, 2 and 5. The minimum of those values is 2.
id |
partno |
rev |
i1 |
1 |
5 |
i1 |
1 |
2 |
i1 |
2 |
3 |
i1 |
3 |
1 |
i2 |
1 |
1 |
i2 |
2 |
2 |
i2 |
5 |
1 |
Order Execution Mgt. Query expression descriptions. |